There is less than a 10% chance to get a Cultist using this method (9.3%)... challenge indeed!
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Highkeeper Ra WITHOUT Cultist
5,360 Dust
4,412 views
Wild
Shuffle Rogue
Ranked
This deck is intended to be a challenge! The goal is to summon Highkeeper Ra without Mogu Cultist in the deck!
We do this by generating a copy with Ravencaller/Jar Dealer!
Then, the combo is Cultist, Tak, and a Scheme above 7! Clear your board and play out the Cultists!
Good luck!
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Comments
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I remember making a Mage deck that relied on generating a Mysterious Challenger using Grand Crusader ...
... It worked once ... in who knows how many tries ^^ -
I wasn't going to do the calculation for that one, but what the hell...
If it was during The Grand Tournament expansion release, it would be a 2.38% chance (approx.)
That's bad, but if it was done in wild format now, it would be a 0.65% chance (approx.)
Even under the best circumstances, you would have to play 42 matches before you could reasonably expect it to happen once...
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It was TGT 's era ^^
I knew back then that the odd were against me, but didn't knew just how bad it was ... thank you for that
The only saving grace is knowing that I lived my meme-dream -
"Never tell me the odds!" :)
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"Ra in every class was too easy for me...
I know! Ra without Cultist in every class!"
+♾
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First time I saw the animation. Its NAISU!
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